Trusses by joints and sections
A truss is a framework of straight members joined at their ends to form triangles. Because a triangle cannot change shape without a member changing length, a truss is rigid and efficient. In the ideal model, joints are frictionless pins and loads are applied only at joints, so every member carries pure axial force: tension or compression, with no bending. Roof trusses, bridge girders, transmission towers and crane booms are all analysed this way first.
A plane truss is statically determinate when m + r = 2j, where m is the number of members, r the number of reaction components and j the number of joints. If m + r is less, it is a mechanism; if more, it is indeterminate and needs deformation methods.
The method of joints isolates each pin. Two equilibrium equations (ΣFx = 0, ΣFy = 0) are available per joint, so start at a joint with no more than two unknown members, usually a support after finding reactions. Work joint to joint. Assume every unknown member is in tension (pulling away from the joint); a negative result means compression. Watch for zero-force members: at an unloaded joint with two non-collinear members, both are zero; at an unloaded joint where two members are collinear, the third is zero.
The method of sections cuts the truss through no more than three members of unknown force and treats one side as a free body with three equations. Taking moments about the point where two of the cut members meet gives the third directly. It is the fastest way to get one member force in the middle of a long truss, and it underlies the influence lines used for moving loads on bridge trusses. Real trusses have rigid joints and self-weight, causing small secondary bending, which design codes deal with separately.
Find the reactions first, then pick the joint or cut that isolates the member you need.
Determinacy (plane truss): m + r = 2jJoints: ΣFx = 0, ΣFy = 0 at each pinSections: ΣFx = 0, ΣFy = 0, ΣM = 0 on the cut partChord force near mid-span ≈ M / h (bending moment over truss depth)
Problem. A Pratt truss 24 m long with 6 panels of 4 m and depth 3 m carries 20 kN at each of the 5 interior bottom joints. Find the bottom chord force in the middle panel.
- Total load 100 kN, reactions 50 kN each by symmetry.
- Cut through the middle panel. Take moments about the top joint above the 3rd bottom joint, 12 m from the left support.
- Moment of external forces left of the cut: 50 × 12 − 20 × (8 + 4) = 600 − 240 = 360 kNm.
- Bottom chord force = 360 / 3 = 120 kN, tension.
Answer. 120 kN tension
Quick quiz
1State the determinacy condition for a plane truss.
m + r = 2j.
2In the method of sections, how many unknown members may be cut?
Generally no more than three.
3At an unloaded joint with two non-collinear members, what are their forces?
Both are zero.
References and further reading
Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.
- F. P. Beer, E. R. Johnston, Vector Mechanics for Engineers: Statics and Dynamics, McGraw Hill, latest edition.
- R. C. Hibbeler, Engineering Mechanics: Statics, Pearson, latest edition.
- S. Timoshenko, D. H. Young, Engineering Mechanics, McGraw Hill, 4th edition, 1956.
Free and official sources
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