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Forces and equilibrium

Basics Engineering Mechanics Reviewed 24 Oct 2026 2 min read

A force is a push or pull with a size, a direction and a point where it acts. Civil engineers deal with forces all day: the weight of a slab, wind on a hoarding, water against a dam, a truck braking on a bridge. Before anything can be designed we must know whether the forces on a body balance.

A body is in equilibrium when it neither starts to move nor starts to rotate. In a flat (two-dimensional) problem that gives exactly three conditions: the forces must add to zero horizontally, add to zero vertically, and their turning effects (moments) about any point must add to zero. Three equations means we can find at most three unknown forces from statics alone, which is why a simply supported beam, with one pin and one roller, can be solved by hand.

PR_AR_B
Diagram: Indiacon original, not to scale.

The working method is always the same. Isolate the body, draw every force acting on it (the free-body diagram), choose a sign convention, then write the three equations. Taking moments about a point where unknown forces meet removes those unknowns from the equation and shortens the algebra.

Equilibrium is the first check on every structure in this library, from a lintel to a cable-stayed bridge. If a structure has more unknown support forces than equations, it is statically indeterminate and needs the deformation methods taught in Structural Analysis.

Tip

Take moments about a support first: one unknown drops out immediately.

Key formulas
  • Sum of horizontal forces: ΣFx = 0
  • Sum of vertical forces: ΣFy = 0
  • Sum of moments about any point: ΣM = 0
Common mistake

Forgetting the self-weight of the member, or using the distance to the wrong end when taking moments.

Solved example

Problem. A 6 m simply supported beam carries a 30 kN point load 2 m from the left support A. Find the support reactions.

  1. Take moments about A: R_B × 6 = 30 × 2, so R_B = 10 kN.
  2. Vertical balance: R_A + R_B = 30, so R_A = 20 kN.
  3. Check by moments about B: R_A × 6 = 30 × 4 = 120, R_A = 20 kN. It matches.

Answer. R_A = 20 kN, R_B = 10 kN

Quick quiz

1How many independent equilibrium equations exist for a 2-D rigid body?

Three: ΣFx = 0, ΣFy = 0 and ΣM = 0.

2Why take moments about a point where unknowns meet?

Those unknowns have zero lever arm about that point, so they drop out of the equation.

3A beam has two pinned supports. Is it determinate under general loading?

No. It has four reaction components and only three equations.

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References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • F. P. Beer, E. R. Johnston, Vector Mechanics for Engineers: Statics and Dynamics, McGraw Hill, latest edition.
  • R. C. Hibbeler, Engineering Mechanics: Statics, Pearson, latest edition.
  • S. Timoshenko, D. H. Young, Engineering Mechanics, McGraw Hill, 4th edition, 1956.

Free and official sources

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