Base isolation and dampers
Base isolation decouples a building from the ground. Flexible bearings, laminated rubber, lead-rubber or curved sliding bearings, are placed between the foundation and the superstructure. They lengthen the fundamental period, typically to 2 seconds or more, moving the building to the low-acceleration part of the response spectrum. The building above moves almost as a rigid block while the bearings take the displacement.
The trade-off is displacement. Lower acceleration comes with larger movement at the isolation level, often 200 to 400 mm in high zones, so services crossing the isolation plane need flexible connections and the building needs a clear moat around it. Damping, from lead cores, high-damping rubber or friction in sliding bearings, limits that movement. Isolation suits stiff, low to medium-rise buildings on firm ground; it suits tall slender buildings less, because they already have long periods.
Supplemental dampers take a different approach: they add energy dissipation within the structure. Viscous fluid dampers in braces, friction dampers, metallic yielding dampers and buckling-restrained braces reduce drift and damage. Tuned mass dampers, a large mass on springs near the top, counter wind sway in tall towers.
Isolated and damped structures are designed with nonlinear analysis and the devices are proof-tested. They are especially valuable for hospitals, emergency centres and buildings housing sensitive equipment, which must stay functional after an earthquake, and for retrofitting heritage buildings.
Isolation works best for stiff low-rise buildings; check the fixed-base period first.
Isolated period: T = 2π √(M / K_iso)Medium soil (IS 1893:2016) spectral shape: S_a/g = 1.36 / T for 0.55 to 4.0 sIsolator displacement (elastic, undamped estimate): D = S_a / ω²
Forgetting that pipes, lifts and cables must cross the isolation gap flexibly.
Problem. A building of mass 2 000 t sits on isolators with total horizontal stiffness 40 000 kN/m. Find the isolated period and compare the medium-soil spectral coefficient with that of the fixed-base building at 0.4 s. Then estimate the displacement for a spectral acceleration of 0.18 × S_a/g × g (zone V, no reduction).
- T = 2π √(2 × 10⁶ kg / 4 × 10⁷ N/m) = 2π √0.05 = 2π × 0.2236 = 1.405 s.
- S_a/g at 1.405 s = 1.36 / 1.405 = 0.968, against 2.5 at 0.4 s: a reduction of about 61 percent.
- S_a = 0.18 × 0.968 × 9.81 = 1.709 m/s²; ω² = K / M = 4 × 10⁷ / 2 × 10⁶ = 20 s⁻².
- D = 1.709 / 20 = 0.085 m, about 85 mm, before damping corrections.
Answer. T ≈ 1.41 s; spectral coefficient falls from 2.5 to about 0.97; displacement about 85 mm
Quick quiz
1How does base isolation reduce forces?
By lengthening the period into the low-acceleration range of the spectrum.
2What is the main cost of isolation?
Large displacement at the isolation level, needing flexible services and a clear gap.
3Name two types of supplemental damper.
Viscous fluid dampers and buckling-restrained braces (also friction or metallic dampers).
- IS 1893 (Part 1) (India): Criteria for earthquake-resistant design: seismic zones and how to work out earthquake forces.
- EN 1998 (Eurocode 8) (Europe): Design of structures for earthquake resistance.
- ASCE/SEI 7 (USA): Minimum design loads (dead, live, wind, snow, seismic) for buildings and other structures.
Cited by number and clause only. We do not reproduce clause text, tables or figures (BIS Act 2016, s.10(5) and s.11). Check the current edition and amendments before use.
References and further reading
Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.
- A. K. Chopra, Dynamics of Structures, Pearson, latest edition.
- T. Paulay, M. J. N. Priestley, Seismic Design of Reinforced Concrete and Masonry Buildings, Wiley, 1992.
- P. Agarwal, M. Shrikhande, Earthquake Resistant Design of Structures, PHI Learning, latest edition.
Free and official sources
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