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Evaporation and infiltration

Intermediate Hydrology Reviewed 24 Oct 2026 2 min read

Evaporation and infiltration are the two biggest losses between rain falling and water arriving at a reservoir or stream. Evaporation turns water into vapour from open water and soil; transpiration does the same through plants; together they form evapotranspiration. In hot, dry parts of India, reservoirs can lose a large depth of water each year to evaporation, a major item in reservoir planning.

Evaporation depends on temperature, humidity, wind, solar radiation and water quality. It is measured with pans, such as the Class A pan, and the pan value is multiplied by a pan coefficient, typically around 0.7, to estimate lake evaporation. It can also be calculated from energy balance or mass transfer methods, or combined methods like Penman. Evaporation from reservoirs can be reduced by monomolecular films, wind breaks, reducing exposed area or floating covers on small storages.

v = k i
Diagram: Indiacon original, not to scale.

Infiltration is water entering the soil surface. Its rate starts high and decreases towards a steady value as the soil wets up. Horton's equation describes this decay; the Green-Ampt and Philip models are more physically based. Infiltration depends on soil texture, structure, moisture, vegetation, compaction and surface sealing. It is measured with double-ring infiltrometers in the field. In flood estimation, infiltration is often lumped into a φ-index. For groundwater recharge, rainwater harvesting and soak pits, high infiltration is what we want.

Tip

Test infiltration at the actual depth and soil where a soak pit or recharge well will be built.

Key formulas
  • Horton: f = fc + (f₀ − fc) e^(−k t)
  • Lake evaporation = pan coefficient × pan evaporation
  • Cumulative infiltration (Horton): F = fc t + (f₀ − fc)(1 − e^(−kt)) / k
Solved example

Problem. A soil has f₀ = 60 mm/h, fc = 10 mm/h and k = 2 per hour. Find the infiltration rate after 1 hour and total infiltration in the first 2 hours.

  1. f(1) = 10 + 50 e^(−2) = 10 + 6.77 = 16.8 mm/h.
  2. F(2) = 10 × 2 + 50 × (1 − e^(−4)) / 2 = 20 + 25 × 0.9817 = 44.5 mm.
  3. So after an initial burst, infiltration settles near 10 mm/h, and longer storms produce more runoff.

Answer. About 16.8 mm/h after 1 h; about 44.5 mm in 2 h

Quick quiz

1What is evapotranspiration?

Combined evaporation from soil and water plus transpiration from plants.

2Why use a pan coefficient?

Pans evaporate more than large lakes, so the pan value is scaled down.

3Which instrument measures field infiltration?

A double-ring infiltrometer.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • K. Subramanya, Engineering Hydrology, McGraw Hill Education (India), latest edition.
  • V. T. Chow, D. R. Maidment, L. W. Mays, Applied Hydrology, McGraw Hill, 1988.

Free and official sources

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