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Energy methods

Advanced and Design Strength of Materials Reviewed 24 Oct 2026 2 min read

When a structure deforms elastically, the work done by the loads is stored as strain energy, like a compressed spring. Energy methods use this to find deflections and to solve indeterminate structures without writing differential equations. They are general, work for trusses, beams and frames alike, and form a bridge to the matrix and finite element methods used in software.

Strain energy for axial load is P² L / (2 A E); for bending, ∫ M² / (2 E I) dx; for torsion, ∫ T² / (2 G J) dx. Castigliano's first theorem gives load from the derivative of energy with respect to displacement, and his second theorem gives the deflection at a load as the partial derivative of total strain energy with respect to that load: δ = ∂U/∂P. If you need deflection where there is no load, add a dummy load Q, differentiate, then set Q = 0. This is equivalent to the unit load method.

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Diagram: Indiacon original, not to scale.

For indeterminate structures, the theorem of least work says that redundant forces take the values that minimise strain energy, so ∂U/∂R = 0 for each redundant. Maxwell's reciprocal theorem states that the deflection at A due to a load at B equals the deflection at B due to the same load at A, which makes flexibility matrices symmetric. Impact problems use energy too: a weight dropped onto a bar produces much larger stress than the same weight applied slowly.

Key formulas
  • Axial: U = P² L / (2AE); bending: U = ∫ M² / (2EI) dx
  • Castigliano: δ = ∂U / ∂P
  • Least work: ∂U / ∂R = 0
  • Sudden load: stress doubles; drop height h: σ = (P/A)[1 + √(1 + 2hAE/(PL))]
Solved example

Problem. Use Castigliano to find the tip deflection of a 3 m cantilever with a 10 kN end load, E I = 2 × 10¹³ Nmm².

  1. M(x) = −P x from the tip; ∂M/∂P = −x.
  2. δ = (1/EI) ∫₀ᴸ P x² dx = P L³ / (3 E I).
  3. = 10 000 × 3 000³ / (3 × 2 × 10¹³) = 10 000 × 2.7 × 10¹⁰ / 6 × 10¹³.
  4. δ = 4.5 mm.

Answer. 4.5 mm downward

Quick quiz

1State Castigliano's second theorem.

The deflection at a load equals the partial derivative of strain energy with respect to that load.

2How do you find deflection where no load acts?

Add a dummy load, differentiate, then set it to zero.

3What does the reciprocal theorem imply for flexibility matrices?

They are symmetric.

References and further reading

Standard texts, listed in no order of merit. We do not copy text, figures, tables or solved problems from any book; our explanations and examples are original.

  • J. M. Gere, B. J. Goodno, Mechanics of Materials, Cengage, latest edition.
  • F. P. Beer, E. R. Johnston, J. T. DeWolf, Mechanics of Materials, McGraw Hill, latest edition.
  • E. P. Popov, Engineering Mechanics of Solids, Prentice Hall, 2nd edition.

Free and official sources

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